我假设您从某种平面模式开始,如下所示:
root |-- lat: double (nullable = false) |-- long: double (nullable = false) |-- key: string (nullable = false)
首先让我们创建示例数据:
import org.apache.spark.sql.Rowimport org.apache.spark.sql.functions.{col, udf}import org.apache.spark.sql.types._val rdd = sc.parallelize( Row(52.23, 21.01, "Warsaw") :: Row(42.30, 9.15, "Corte") :: Nil)val schema = StructType( StructField("lat", DoubleType, false) :: StructField("long", DoubleType, false) :: StructField("key", StringType, false) ::Nil)val df = sqlContext.createDataframe(rdd, schema)一种简单的方法是使用udf和case类:
case class Location(lat: Double, long: Double)val makeLocation = udf((lat: Double, long: Double) => Location(lat, long))val dfRes = df. withColumn("location", makeLocation(col("lat"), col("long"))). drop("lat"). drop("long")dfRes.printSchema我们得到
root |-- key: string (nullable = false) |-- location: struct (nullable = true) | |-- lat: double (nullable = false) | |-- long: double (nullable = false)
一种困难的方法是转换数据并随后应用模式:
val rddRes = df. map{case Row(lat, long, key) => Row(key, Row(lat, long))}val schemaRes = StructType( StructField("key", StringType, false) :: StructField("location", StructType( StructField("lat", DoubleType, false) :: StructField("long", DoubleType, false) :: Nil ), true) :: Nil )sqlContext.createDataframe(rddRes, schemaRes).show我们得到了预期的输出
+------+-------------+| key| location|+------+-------------+|Warsaw|[52.23,21.01]|| Corte| [42.3,9.15]|+------+-------------+
从头开始创建嵌套模式可能很繁琐,因此,如果可以的话,我建议您采用第一种方法。如果需要更复杂的结构,可以轻松扩展它:
case class Pin(location: Location)val makePin = udf((lat: Double, long: Double) => Pin(Location(lat, long))df. withColumn("pin", makePin(col("lat"), col("long"))). drop("lat"). drop("long"). printSchema我们得到预期的输出:
root |-- key: string (nullable = false) |-- pin: struct (nullable = true) | |-- location: struct (nullable = true) | | |-- lat: double (nullable = false) | | |-- long: double (nullable = false)
不幸的是,您无法控制
nullable字段,因此如果对您的项目很重要,则必须指定架构。
最后,您可以使用
struct1.4中引入的功能:
import org.apache.spark.sql.functions.structdf.select($"key", struct($"lat", $"long").alias("location"))


