用Python发送100,000个HTTP请求的最快方法是什么？

无捻解决方案：

from urlparse import urlparsefrom threading import Threadimport httplib, sysfrom Queue import Queueconcurrent = 200def doWork():    while True:        url = q.get()        status, url = getStatus(url)        doSomethingWithResult(status, url)        q.task_done()def getStatus(ourl):    try:        url = urlparse(ourl)        conn = httplib.HTTPConnection(url.netloc)conn.request("HEAD", url.path)        res = conn.getresponse()        return res.status, ourl    except:        return "error", ourldef doSomethingWithResult(status, url):    print status, urlq = Queue(concurrent * 2)for i in range(concurrent):    t = Thread(target=doWork)    t.daemon = True    t.start()try:    for url in open('urllist.txt'):        q.put(url.strip())    q.join()except KeyboardInterrupt:    sys.exit(1)

这比扭曲的解决方案要快一点，并且使用的CPU更少。