Python：如何根据对象的特征或属性对对象列表进行分组？[重复]

看一看

itertools.groupby()

>>> from itertools import groupby>>> l = ["This", "is", "a", "sentence", "of", "seven", "words"]>>> print [list(g[1]) for g in groupby(sorted(l, key=len), len)][['a'], ['is', 'of'], ['This'], ['seven', 'words'], ['sentence']]

或者如果您想要 字典 ->

>>> {k:list(g) for k, g in groupby(sorted(l, key=len), len)}{8: ['sentence'], 1: ['a'], 2: ['is', 'of'], 4: ['This'], 5: ['seven', 'words']}