Java中包含数字的排序字符串

尝试使用此比较器，该比较器将删除所有非数字字符，然后将其余字符与数字进行比较：

Collections.sort(strings, new Comparator<String>() {    public int compare(String o1, String o2) {        return extractInt(o1) - extractInt(o2);    }    int extractInt(String s) {        String num = s.replaceAll("\D", "");        // return 0 if no digits found        return num.isEmpty() ? 0 : Integer.parseInt(num);    }});

这是一个测试：

public static void main(String[] args) throws IOException {    List<String> strings = Arrays.asList("room1.2", "foo1.1", "foo", "room2.3", "room100.999", "room10", "room.3");    Collections.sort(strings, new Comparator<String>() {        public int compare(String o1, String o2) { return extractInt(o1) - extractInt(o2);        }        int extractInt(String s) { String num = s.replaceAll("\D", ""); // return 0 if no digits found return num.isEmpty() ? 0 : Integer.parseInt(num);        }    });    System.out.println(strings);}

输出：

[foo, room1, room2, room10, room100]

当数字为小数时（也表示Java 8+样式）：

public static void main(String[] args) {    List<String> strings = Arrays.asList("room1.2", "foo1.1", "room2.3", "room100.999", "room10", "room.3");    Collections.sort(strings, Comparator.comparing(Application::extractDouble));    System.out.println(strings);}static double extractDouble(String s) {    String num = s.replaceAll("[^\d.]", "");    // return 0 if no digits found    return num.isEmpty() ? 0 : Double.parseDouble(num);}

结果：

[foo, room.3, foo1.1, room1.2, room2.3, room10, room100.999]