我认为第一个数字（
1325134800000）是自纪元以来的毫秒数，并且
-0500是时区。鉴于以下示例代码似乎是这种情况，它似乎可以满足您的要求。
以下代码使用Jackson解析JSON输入，如果您还没有选择的JSON解析库，我建议您这样做。它缺少错误检查等。
样例代码：
public final class Foo{ public static void main(final String... args) throws IOException { // What the JSON value must match exactly // Not anchored since it will be used with the (misnamed) .matches() method final Pattern pattern = Pattern.compile("\\/Date\((\d+)(-\d+)?\)\\/"); final ObjectMapper mapper = new ObjectMapper(); // Parse JSON... final JsonNode node = mapper.readTree( "{"PostingDate": "\/Date(1325134800000-0500)\/"}"); if (!node.has("PostingDate")) { System.err.println("Bad JSON input!"); System.exit(1); } // Get relevant field final String dateSpec = node.get("PostingDate").getTextValue(); // Try and match the input. final Matcher matcher = pattern.matcher(dateSpec); if (!matcher.matches()) { System.err.println("Bad pattern!"); // Yuck System.exit(1); } // The first group capture the milliseconds, the second one the time zone final long millis = Long.parseLong(matcher.group(1)); String tz = matcher.group(2); if (tz.isEmpty()) // It can happen, in which case the default is assumed to be... tz = "+0000"; // Instantiate a date object... final Date date = new Date(millis); // And print it using an appropriate date format System.out.printf("Date: %s %sn", new SimpleDateFormat("yyyy/MM/dd HH:MM:ss").format(date), tz); }}输出：
Date: 2011/12/29 06:12:00 -0500
