2021-10-31

#include
#pragma warning(disable:4996)

//输出指定个数的斐波那契数列

int main()
{
	int a, b = 0, c = 1;
	printf("输出的斐波那契数列的个数为");
	scanf("%d", &a);
	for (int i = 0; i < a; i+=2)
	{
		printf("%dn", b);
		c = c + b;		//1 2 5
		b = b + c;		//1 3 8
		printf("%dn", c);

	}
}

#include
#pragma warning(disable:4996)

int main()
{
	int a, b, c, e;
	scanf("%d%d", &a, &b);
	int d = a * b;
	while (a != 0)
	{
		c = b % a;
		b = a;
		a = c;
	}
	e = d / b;
	printf("%d", e);
}

#include
#pragma warning(disable:4996)

void main()
{
	int a,b=0;
	scanf("%d", &a);
	do
	{
		b++;
		a = a / 10;
	} while (a>10);
	printf("%d", b);
}

#include

void main()
{
    int input,a,b=0,c;
    scanf("%d",&input);
	c=input;
    while(c!=0)
    {
        a = c%10;
        b = b*10 + a;
        c /= 10;
    }
    if(b==input)    
	{
		printf("是回文数n");
	}
    else
	{
		printf("不是回文数n");
	}		
}

#include
#include
#pragma warning(disable:4996)


int main()
{
	int a,n,t;
	scanf("%d%d", &a,&n);
	t = pow(a, n);
	printf("%d的%d次方为%d", a, n, t);
}

#include
#pragma warning(disable:4996)

int main()
{
	int a, total = 1, j = 1;
	scanf("%d", &a);
	for (int i = 0; i < a; i++)
	{
		total *= j;
		j++;
	}
	printf("%dn", total);
	return 0;
}