如何使用Jest测试异步存储？

我最初的回答只是指出react-native-simple-store的作者如何处理模拟。我用自己的模拟更新了答案，该模拟除去了Jason的硬编码模拟响应。

Jason
Merino
在https://github.com/jasonmerino/react-
native-simple-store/blob/master/
tests /index-
test.js#L31-L64有一个很好的简单方法
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jest.mock('react-native', () => ({AsyncStorage: {    setItem: jest.fn(() => {        return new Promise((resolve, reject) => { resolve(null);        });    }),    multiSet:  jest.fn(() => {        return new Promise((resolve, reject) => { resolve(null);        });    }),    getItem: jest.fn(() => {        return new Promise((resolve, reject) => { resolve(JSON.stringify(getTestData()));        });    }),    multiGet: jest.fn(() => {        return new Promise((resolve, reject) => { resolve(multiGetTestData());        });    }),    removeItem: jest.fn(() => {        return new Promise((resolve, reject) => { resolve(null);        });    }),    getAllKeys: jest.fn(() => {        return new Promise((resolve) => { resolve(['one', 'two', 'three']);        });    })  }}));

我自己的模拟：

const items = {};jest.mock('react-native', () => ({AsyncStorage: {    setItem: jest.fn((item, value) => {        return new Promise((resolve, reject) => { items[item] = value; resolve(value);        });    }),    multiSet:  jest.fn((item, value) => {        return new Promise((resolve, reject) => {    items[item] = value; resolve(value);        });    }),    getItem: jest.fn((item, value) => {        return new Promise((resolve, reject) => { resolve(items[item]);        });    }),    multiGet: jest.fn((item) => {        return new Promise((resolve, reject) => { resolve(items[item]);        });    }),    removeItem: jest.fn((item) => {        return new Promise((resolve, reject) => { resolve(delete items[item]);        });    }),    getAllKeys: jest.fn((items) => {        return new Promise((resolve) => { resolve(items.keys());        });    })  }}));