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有人可以解释Java语言中的“反跳”功能吗

面试问答 更新时间: 发布时间: IT归档 最新发布 模块sitemap 名妆网 法律咨询 聚返吧 英语巴士网 伯小乐 网商动力

有人可以解释Java语言中的“反跳”功能吗

问题中的代码与链接中的代码略有不同。在链接中,

(immediate&&!timeout)
在创建新的timout之前要进行检查。之后拥有它会导致即时模式从不触发。我已经更新了答案,以便从链接中注释工作版本。

function debounce(func, wait, immediate) {  // 'private' variable for instance  // The returned function will be able to reference this due to closure.  // Each call to the returned function will share this common timer.  var timeout;  // Calling debounce returns a new anonymous function  return function() {    // reference the context and args for the setTimeout function    var context = this,      args = arguments;    // Should the function be called now? If immediate is true    //   and not already in a timeout then the answer is: Yes    var callNow = immediate && !timeout;    // This is the basic debounce behaviour where you can call this    //   function several times, but it will only execute once    //   [before or after imposing a delay].    //   Each time the returned function is called, the timer starts over.    clearTimeout(timeout);    // Set the new timeout    timeout = setTimeout(function() {      // Inside the timeout function, clear the timeout variable      // which will let the next execution run when in 'immediate' mode      timeout = null;      // Check if the function already ran with the immediate flag      if (!immediate) {        // Call the original function with apply        // apply lets you define the 'this' object as well as the arguments        //    (both captured before setTimeout)        func.apply(context, args);      }    }, wait);    // Immediate mode and no wait timer? Execute the function..    if (callNow) func.apply(context, args);  }}/////////////////////////////////// DEMO:function onMouseMove(e){  console.clear();  console.log(e.x, e.y);}// Define the debounced functionvar debouncedMouseMove = debounce(onMouseMove, 50);// Call the debounced function on every mouse movewindow.addEventListener('mousemove', debouncedMouseMove);


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