假设您在后端中期望Multipart，这是一段对我有用的代码。
这是一个jsfiddle。
var app = angular.module('myApp', [])app.controller('MyController', function MyController($scope, $http) { //the image $scope.uploadme; $scope.uploadImage = function() { var fd = new FormData(); var imgBlob = dataURItoBlob($scope.uploadme); fd.append('file', imgBlob); $http.post( 'imageURL', fd, { transformRequest: angular.identity, headers: { 'Content-Type': undefined } } ) .success(function(response) { console.log('success', response); }) .error(function(response) { console.log('error', response); }); } //you need this function to convert the dataURI function dataURItoBlob(dataURI) { var binary = atob(dataURI.split(',')[1]); var mimeString = dataURI.split(',')[0].split(':')[1].split(';')[0]; var array = []; for (var i = 0; i < binary.length; i++) { array.push(binary.charCodeAt(i)); } return new Blob([new Uint8Array(array)], { type: mimeString }); } });//your directiveapp.directive("fileread", [ function() { return { scope: { fileread: "=" }, link: function(scope, element, attributes) { element.bind("change", function(changeEvent) { var reader = new FileReader(); reader.onload = function(loadEvent) { scope.$apply(function() { scope.fileread = loadEvent.target.result; }); } reader.readAsDataURL(changeEvent.target.files[0]); }); } } }]);<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script><div ng-app="myApp"> <div ng-controller="MyController"> <input type="file" fileread="uploadme" /> <img src="{{uploadme}}" width="100" height="50" alt="Image preview..."> <br/> <p> Image dataURI: <pre>{{uploadme}}</pre> </p> <br/> <button ng-click="uploadImage()">upload image</button> </div></div>请注意 以下部分：
{ transformRequest: angular.identity, headers: { 'Content-Type': undefined }}是一些Angular魔术，为了使$ http解析FormData并找到正确的内容类型，等等。
