如何在Go中将[4] uint8转换为uint32？

package mainimport (    "encoding/binary"    "fmt")func main() {    u8 := []uint8{0, 1, 2, 3}    u32LE := binary.LittleEndian.Uint32(u8)    fmt.Println("little-endian:", u8, "to", u32LE)    u32BE := binary.BigEndian.Uint32(u8)    fmt.Println("big-endian:   ", u8, "to", u32BE)}

输出：

little-endian: [0 1 2 3] to 50462976big-endian:    [0 1 2 3] to 66051

Go 二进制包功能通过一系列移位实现。

func (littleEndian) Uint32(b []byte) uint32 {    return uint32(b[0]) | uint32(b[1])<<8 | uint32(b[2])<<16 | uint32(b[3])<<24}func (bigEndian) Uint32(b []byte) uint32 {    return uint32(b[3]) | uint32(b[2])<<8 | uint32(b[1])<<16 | uint32(b[0])<<24}