如果它包含html（请注意，这是一个非常强大的解决方案）：
$string = '<p>foo<b>bar</b></p>';$keyword = 'foo';$dom = new Domdocument();$dom->loadHtml($string);$xpath = new DomXpath($dom);$elements = $xpath->query('//*[contains(.,"'.$keyword.'")]');foreach ($elements as $element) { foreach ($element->childNodes as $child) { if (!$child instanceof DomText) continue; $fragment = $dom->createdocumentFragment(); $text = $child->textContent; $stubs = array(); while (($pos = stripos($text, $keyword)) !== false) { $fragment->appendChild(new DomText(substr($text, 0, $pos))); $word = substr($text, $pos, strlen($keyword)); $highlight = $dom->createElement('span'); $highlight->appendChild(new DomText($word)); $highlight->setAttribute('class', 'highlight'); $fragment->appendChild($highlight); $text = substr($text, $pos + strlen($keyword)); } if (!empty($text)) $fragment->appendChild(new DomText($text)); $element->replaceChild($fragment, $child); }}$string = $dom->saveXml($dom->getElementsByTagName('body')->item(0)->firstChild);结果是：
<p><span >foo</span><b>bar</b></p>
与：
$string = '<body><p>foobarbaz<b>bar</b></p></body>';$keyword = 'bar';
您得到（为了便于阅读，分为多行）：
<p>foo <span >bar</span> baz <b> <span >bar</span> </b></p>
提防非dom解决方案（如
regex或
str_replace），因为突出显示诸如“
div”之类的东西有完全破坏HTML的趋势……这只会在正文中“突出显示”字符串，而不会在标签内……
编辑 由于需要Google样式的结果，因此这是一种处理方法：
function getKeywordStubs($string, array $keywords, $maxStubSize = 10) { $dom = new Domdocument(); $dom->loadHtml($string); $xpath = new DomXpath($dom); $results = array(); $maxStubHalf = ceil($maxStubSize / 2); foreach ($keywords as $keyword) { $elements = $xpath->query('//*[contains(.,"'.$keyword.'")]'); $replace = '<span >'.$keyword.'</span>'; foreach ($elements as $element) { $stub = $element->textContent; $regex = '#^.*?((w*W*){'. $maxStubHalf.'})('. preg_quote($keyword, '#'). ')((w*W*){'. $maxStubHalf.'}).*?$#ims'; preg_match($regex, $stub, $match); var_dump($regex, $match); $stub = preg_replace($regex, '\1\3\4', $stub); $stub = str_ireplace($keyword, $replace, $stub); $results[] = $stub; } } $results = array_unique($results); return $results;}好的，所以要做的就是返回一个包含
$maxStubSize单词的匹配数组（即该数字之前的一半，之后的一半）…
因此，给定一个字符串：
<p>a whole <b>bunch of</b> text <a>here for</a> us to foo bar baz replace out from this string <b>bar</b></p>
调用
getKeywordStubs($string, array('bar', 'bunch'))将导致：array(4) { [0]=> string(75) "here for us to foo <span >bar</span> baz replace out from " [3]=> string(34) "<span >bar</span>" [4]=> string(62) "a whole <span >bunch</span> of text here for " [7]=> string(39) "<span >bunch</span> of"}所以，那么您可以通过对列表进行排序
strlen，然后选择两个最长的匹配项来构建结果blurb （假设php 5.3+）：
usort($results, function($str1, $str2) { return strlen($str2) - strlen($str1);});$description = implode('...', array_slice($results, 0, 2));结果是：
here for us to foo <span >bar</span> baz replace out...a whole <span >bunch</span> of text here for
我希望有帮助…（我确实觉得这有点......肿…我敢肯定有更好的方法可以做到这一点，但这是一种方法）…
