如何获取XML子节点作为字符串以及父属性？

select        c.value('@Description', 'varchar(max)') as 'Description'        , c.query('./nodeB')  as Contentfrom @xml.nodes('/root/*') as T(c)-- Results to:Description Contentfirstgroup  <nodeB mode="A" ability="read" />nextgroup   <nodeB count="2" birthplace="Paris" />