间歇性Python线程错误，“主线程不在主循环中”

您需要在主线程中运行GUI代码，而温度读取代码需要在后台线程中。仅在主线程中更新GUI是安全的，因此您可以通过将从后台线程读取的温度数据通过传递回主线程

Queue

self.root.after()

from Tkinter import *import tkFontimport osimport globimport timeimport threadingimport Image import Queuedef update_temp(queue):    """ Read the temp data. This runs in a background thread. """    while True:        #   28-000005c6ba08        i = "28-000005c6ba08"        base_dir = '/sys/bus/w1/devices/'        device_folder = glob.glob(base_dir + i)[0]        device_file = device_folder + '/w1_slave'        tempread=round(read_temp(),1)        # Pass the temp back to the main thread.        queue.put(tempread)        time.sleep(5)class Gui(object):    def __init__(self, queue):        self.queue = queue        #Make the window        self.root = Tk()         self.root.wm_title("Home Management System")        self.root.minsize(1440,1000)        self.equipTemp = StringVar()self.equipTemp1 = StringVar()        self.equipTemp2 = StringVar()        self.customFont = tkFont.Font(family="Helvetica", size=16)        #   1st floor Image        img = Image.open("HOUSE-PLANS-01.png")         photo = ImageTk.PhotoImage(img)        Label1=Label(self.root, image=photo)        Label1.place(x=100, y=100)        #   2nd floor        img2 = Image.open("HOUSE-PLANS-02.png")        photo2 = ImageTk.PhotoImage(img2)        Label1=Label(self.root, image=photo2)        Label1.place(x=600, y=100)        #   basement image        img3 = Image.open("HOUSE-PLANS-03.png")        photo3 = ImageTk.PhotoImage(img3)        Label1=Label(self.root, image=photo3)        Label1.place(x=100, y=500)        #   Attic Image        img4 = Image.open("HOUSE-PLANS-04.png")        photo4 = ImageTk.PhotoImage(img4)        Label1=Label(self.root, image=photo4)        Label1.place(x=600, y=500)        #   House Isometric Image        img5 = Image.open("house-iso.png")        photo5 = ImageTk.PhotoImage(img5)        Label1=Label(self.root, image=photo5)        Label1.place(x=1080, y=130)        #Garage Temp Label        Label2=Label(self.root, textvariable=self.equipTemp, width=6, justify=RIGHT, font=self.customFont)        Label2.place(x=315, y=265)        print "start monitoring and updating the GUI"        # Schedule read_queue to run in the main thread in one second.        self.root.after(1000, self.read_queue)    def read_queue(self):        """ Check for updated temp data"""        try: temp = self.queue.get_nowait() self.equipTemp.set(temp)        except Queue.Empty: # It's ok if there's no data to read. # We'll just check again later. pass        # Schedule read_queue again in one second.        self.root.after(1000, self.read_queue)if __name__ == "__main__":    queue = Queue.Queue()    # Start background thread to get temp data    t = threading.Thread(target=update_temp, args=(queue,))    t.start()    print "starting app"    # Build GUI object    gui = Gui(queue)    # Start mainloop    gui.root.mainloop()

编辑：

之后实际上正在看看Tkinter的源代码，以及Python的bug跟踪系统，似乎与几乎所有其它的GUI库那里，Tkinter的 是
意是线程安全的，只要你在主线程中运行的主循环的应用程序。见我添加的答案在这里获得更多信息，或者直接去解决问题，关于Python的bug跟踪系统的Tkinter的线程安全性在这里。如果tkinter源代码和Python的错误跟踪器是正确的，那意味着只要您在主线程中运行mainloop，就可以

gui.equipTemp.set()

Queue