返回带有错误状态代码MVC的JSON

我在这里找到解决方案

我必须创建一个动作过滤器来覆盖MVC的默认行为

这是我的异常类

class ValidationException : ApplicationException{    public JsonResult exceptionDetails;    public ValidationException(JsonResult exceptionDetails)    {        this.exceptionDetails = exceptionDetails;    }    public ValidationException(string message) : base(message) { }    public ValidationException(string message, Exception inner) : base(message, inner) { }    protected ValidationException(    System.Runtime.Serialization.SerializationInfo info,    System.Runtime.Serialization.StreamingContext context)        : base(info, context) { }}

请注意，我有用于初始化JSON的构造函数。这是动作过滤器

public class HandleUIExceptionAttribute : FilterAttribute, IExceptionFilter{    public virtual void onException(ExceptionContext filterContext)    {        if (filterContext == null)        { throw new ArgumentNullException("filterContext");        }        if (filterContext.Exception != null)        { filterContext.ExceptionHandled = true; filterContext.HttpContext.Response.Clear(); filterContext.HttpContext.Response.TrySkipIisCustomErrors = true; filterContext.HttpContext.Response.StatusCode = (int)System.Net.HttpStatusCode.InternalServerError; filterContext.Result = ((ValidationException)filterContext.Exception).myJsonError;        }    }

现在有了动作过滤器，我将用filter属性装饰控制器

[HandleUIException]public JsonResult UpdateName(string objectToUpdate){   var response = myClient.ValidateObject(objectToUpdate);   if (response.errors.Length > 0)     throw new ValidationException(Json(response));}

引发错误时，将调用实现IExceptionFilter的动作过滤器，并在错误回调上返回客户端上的Json。