一个简单的循环
var a = [{level:1},{level:2},{level:3},{level:4}], total = 0; for (var i=0; i<a.length; i++) { total += a[i].level; }console.log('total', total)或减少
var a = [{level:1},{level:2},{level:3},{level:4}]console.log(a.reduce( function(cnt,o){ return cnt + o.level; }, 0))


