这是一个奇怪的结果。我发现，如果您颠倒了点的顺序，则会绘制出完整的图形。换一种说法：
# this is brokenpts = [(1, 1), (1, 10), (10, 10), (10, 1)]# this workspts = [(1, 1), (10, 1), (10, 10), (1, 10)]
这是一个测试程序：
import numpyimport mahotas.polygondef run(n, reverse=0): canvas = numpy.zeros((n, n), dtype=int) lim = n-2 print 'n%d x %d, lim=%d reverse=%d' % (n, n, lim, reverse) pts = [(1, 1), (1, lim), (lim, lim), (lim, 1), (1, 1)] if reverse: pts.reverse() mahotas.polygon.fill_polygon(pts, canvas) return canvasfor rev in (0, 1): for n in range(3, 14): print run(n, rev)
例子：
6 x 6, lim=4 reverse=0[[0 0 0 0 0 0] [0 1 0 0 1 0] [0 1 1 1 1 0] [0 1 1 1 1 0] [0 1 0 0 0 0] [0 0 0 0 0 0]]6 x 6, lim=4 reverse=1[[0 0 0 0 0 0] [0 1 1 1 1 0] [0 1 1 1 1 0] [0 1 1 1 1 0] [0 1 1 1 1 0] [0 0 0 0 0 0]]
