使用JS / JQUERY发布AJAX请求。 以下是我用于所有AJAX调用的语法。
var first = 'something';var second = 'second';var third = $("#some_input_on_your_page").val();///////// AJAX //////// AJAX ////////// $.ajax({ type: 'POST', url: 'page_that_receives_post_variables.php', data: {first:first, second:second, third:third}, success: function( response ){ alert('yay ajax is done.'); $('#edit_box').html(response);//this is where you populate your response }//close succss params });//close ajax///////// AJAX //////// AJAX //////////PHP页面page_that_receives_post_variables.php的代码
<?php$first = $_POST['first'];$second = $_POST['second'];$third = $_POST['third'];echo 'now do something with the posted items.';echo $first; //etc...?>
