如何在Golang中返回动态类型struct？

是的，但是您的函数应该返回

interface{}

[]*interface

func (c Helper) ReturnModels(modelName string) interface{} {}

在这种情况下，您可以使用类型开关和/或类型断言将返回值转换为原始类型。

例

注意：我从未使用过Revel，但是以下代码片段应该为您提供一个总体思路：

操场

package mainimport "fmt"type Post struct {    Author  string    Content string}type Brand struct {    Name string}var database map[string]interface{}func init() {    database = make(map[string]interface{})    brands := make([]Brand, 2)    brands[0] = Brand{Name: "Gucci"}    brands[1] = Brand{Name: "LV"}    database["brands"] = brands    posts := make([]Post, 1)    posts[0] = Post{Author: "J.K.R", Content: "Whatever"}    database["posts"] = posts}func main() {    fmt.Println("List of Brands: ")    if brands, ok := ReturnModels("brands").([]Brand); ok {        fmt.Printf("%v", brands)    }    fmt.Println("nList of Posts: ")    if posts, ok := ReturnModels("posts").([]Post); ok {        fmt.Printf("%v", posts)    }}func ReturnModels(modelName string) interface{} {    return database[modelName]}