2D列表中的Python计数元素频率[重复]

假设我了解你想要什么，

>>> collections.Counter([x for sublist in a for x in sublist])Counter({'mrpycharm': 3, 'its': 2, 'friends': 1, 'is': 1, 'it': 1, 'hello': 1})

要么，

>>> c = collections.Counter()>>> for sublist in a:...     c.update(sublist)...>>> cCounter({'mrpycharm': 3, 'its': 2, 'friends': 1, 'is': 1, 'it': 1, 'hello': 1})