#include <iostream>#include <stdio.h>#include <string.h>using namespace std;#define MAXT 26#define MAXE 1000#define INF INT_MAXtypedef struct{int s,t,w;}Edge;Edge edge[MAXE];int r[MAXT];//某个小时需要多少人int t[MAXT];//在第i个小时应聘的人数int d[MAXT];int n,edgesum,ans;void add(int s,int t,int w){edge[edgesum].s=s;edge[edgesum].t=t;edge[edgesum++].w=w;}void buildgragh(int x){int i;edgesum=48;for(i=1;i<=16;i++) add(i+8,i,-r[i+8]);for(i=17;i<=24;i++) add(i-16,i,x-r[i-16]);add(24,0,-x);}int bellman_ford(){int i,j;for(i=0;i<=24;i++) d[i]=INF;d[0]=0;for(i=0;i<=24;i++){for(j=0;j<edgesum;j++){if(d[edge[j].s]+edge[j].w<d[edge[j].t]){d[edge[j].t]=d[edge[j].s]+edge[j].w;}}}for(j=0;j<edgesum;j++){//判断是否有负环if(d[edge[j].s]+edge[j].w<d[edge[j].t]){return 0;}}return 1;}void Besearch(int low,int high){if(low>high) return;int mid=(low+high)/2;buildgragh(mid);if(bellman_ford()){ans=mid;Besearch(low,mid-1);}else{Besearch(mid+1,high);}}int main(){int i,Case,x;scanf("%d",&Case);while(Case--){memset(t,0,sizeof(t));for(i=1;i<=24;i++) scanf("%d",&r[i]);scanf("%d",&n);for(i=1;i<=n;i++){//x+1时刻的应聘人数加1scanf("%d",&x);t[x+1]++;}edgesum=0;for(i=1;i<=24;i++){//这48条边是固定的，每个图都需要add(i-1,i,t[i]);add(i,i-1,0);}ans=-1;//对人数二分枚举求解Besearch(0,n);if(ans==-1) printf("No Solutionn"); else printf("%dn",ans);}return 0;}
