需要将JSON中的整数解析为整数，而不是浮点数

例如，使用通用Go机制获取自定义JSON值的Ruby JSON数字类型，

package mainimport (    "encoding/json"    "fmt"    "strconv")func main() {    str := `{"a":123,"b":12.3,"c":"123","d":"12.3","e":true}`    var raw map[string]json.RawMessage    err := json.Unmarshal([]byte(str), &raw)    if err != nil {        panic(err)    }    parsed := make(map[string]interface{}, len(raw))    for key, val := range raw {        s := string(val)        i, err := strconv.ParseInt(s, 10, 64)        if err == nil { parsed[key] = i continue        }        f, err := strconv.ParseFloat(s, 64)        if err == nil { parsed[key] = f continue        }        var v interface{}        err = json.Unmarshal(val, &v)        if err == nil { parsed[key] = v continue        }        parsed[key] = val    }    for key, val := range parsed {        fmt.Printf("%T: %v %vn", val, key, val)    }}

游乐场：https :
//play.golang.org/p/VmG8IZV4CG_Y

输出：

int64: a 123 float64: b 12.3 string: c 123 string: d 12.3 bool: e true

另一个示例，使用Go

json.Number

package mainimport (    "encoding/json"    "fmt"    "strings")func main() {    str := `{"a":123,"b":12.3,"c":"123","d":"12.3","e":true}`    var parsed map[string]interface{}    d := json.NewDeprer(strings.NewReader(str))    d.UseNumber()    err := d.Depre(&parsed)    if err != nil {        panic(err)    }    for key, val := range parsed {        n, ok := val.(json.Number)        if !ok { continue        }        if i, err := n.Int64(); err == nil { parsed[key] = i continue        }        if f, err := n.Float64(); err == nil { parsed[key] = f continue        }    }    for key, val := range parsed {        fmt.Printf("%T: %v %vn", val, key, val)    }}

游乐场：https :
//play.golang.org/p/Hk_Wb0EM-aY

输出：

int64: a 123float64: b 12.3string: c 123string: d 12.3bool: e true

@ShudiptaSharma建议的工作版本。