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poj 2066 Minimax Triangulation

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poj 2066 Minimax Triangulation

#include <cstdio>#include <iostream>#include <cstring>#include <cmath>using namespace std;#define MAX 55const int INF = (1<<30);struct node{ int x, y;}p[MAX];int n;int dp[MAX][MAX];inline int max(int a, int b){ return a > b ? a : b;}inline int min(int a, int b){ return a < b ? a : b;}inline int multiply(node A, node B){ return A.x*B.y - A.y*B.x;}inline int area(node A, node B, node C){ int size = multiply(A, B)+multiply(B, C)+multiply(C, A); return size > 0 ? size : (-size);}inline bool judge(int i, int j, int k){ int size = area(p[i], p[j], p[k]); for(int t = 1; t <= n; ++t) {  if(t == i || t == j || t == k) continue;  int temp = area(p[i], p[j], p[t])+area(p[i], p[k], p[t])+area(p[j], p[k], p[t]);  if(size == temp) return false; } return true;}int main(){ int i, j, k;// freopen("input.txt", "r", stdin); int caseNum; scanf("%d", &caseNum); while(caseNum--) {  scanf("%d", &n);  for(i = 1; i <= n; ++i)   scanf("%d %d", &p[i].x, &p[i].y);  memset(dp, 0, sizeof(dp));  for(i = 1; i <= n-2; ++i)   dp[i][i+2] = area(p[i], p[i+1], p[i+2]);  int temp1, temp2, temp3;  for(int q = 3; q < n; ++q)  {   for(i = 1; i+q <= n; ++i)   {    j = i+q;    temp1 = INF;    if( judge(i, i+1, j) )     temp1 = max(area(p[i], p[i+1], p[j]), dp[i+1][j]);    if( judge(i, j-1, j) )    {     temp2 = max(area(p[i], p[j-1], p[j]), dp[i][j-1]);     temp1 = min(temp1, temp2);    }    for(k = i+2; k <= j-2; ++k)    {     if( !judge(i, j, k) ) continue;     temp2 = area(p[i], p[j], p[k]);     temp3 = dp[i][k];     temp2 = max(temp2, temp3);     temp3 = dp[k][j];     temp2 = max(temp2, temp3);     temp1 = min(temp1, temp2);    }    dp[i][j] = temp1;   }  }  printf("%d", dp[1][n]/2);  if(dp[1][n] % 2 == 1) printf(".5n");  else printf(".0n"); } return 0;}
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