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poj 1015 Jury Compromise

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poj 1015 Jury Compromise

#include<stdio.h>#include<stdlib.h>#include<string.h>int f[ 30 ][ 1000 ];int Path[ 30 ][ 1000 ];int P[ 300 ];int D[ 300 ];int Answer[ 30 ];int CompareInt( const void* e1, const void* e2 ){return* ( ( int* )e1 ) - *( ( int* )e2 );}int main(){int i, j, k;int t1, t2;int n, m;int nMinP_D;int nCaseNo;nCaseNo = 0;scanf( "%d%d", &n, &m );while( n + m ){nCaseNo++;for( i = 1; i <= n; i++ )scanf( "%d%d", &P[ i ], &D[ i ] );memset( f, -1, sizeof( f ) );memset( Path, 0, sizeof( Path ) );nMinP_D = m * 20;f[ 0 ][ nMinP_D ] = 0;for( j = 0; j < m; j++ ){for( k = 0; k <= nMinP_D * 2; k++ )if( f[ j ][ k ] >= 0 ){for( i = 1; i <= n; i++ )if( f[ j ][ k ] + P[ i ] + D[ i ] > f[ j + 1 ][ k + P[ i ] - D[ i ] ] ){t1 = j;t2 = k;while( t1 > 0 && Path[ t1 ][ t2 ] != i ){t2 -= P[ Path[ t1 ][ t2 ] ] - D[ Path[ t1 ][ t2 ] ];t1--;}if( t1 == 0 ){f[ j + 1 ][ k + P[ i ] - D[ i ] ] = f[ j ][ k ] + P[ i ] + D[ i ];Path[ j + 1 ][ k + P[ i ] - D[ i ] ] = i;}}}}i = nMinP_D;j = 0;while( f[ m ][ i + j ] < 0 && f[ m ][ i - j ] < 0 )j++;if( f[ m ][ i + j ] > f[ m ][ i - j ] )k = i + j;elsek = i - j;printf( "Jury #%dn", nCaseNo );printf( "Best jury has value %d for prosecution and value %d for defence:n", ( k - nMinP_D + f[ m ][ k ] )/ 2, ( f[ m ][ k ] - k + nMinP_D )/2 ); for( i = 1; i <= m; i++ ){Answer[ i ] = Path[ m - i + 1 ][ k ];k -= P[ Answer[ i ] ] - D[ Answer[ i ] ];}qsort( Answer + 1, m, sizeof( int ), CompareInt );for( i = 1; i <= m; i++ )printf( " %d", Answer[ i ] );printf( "n" );printf( "n" );scanf( "%d%d", &n, &m );}return 0;}
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