使用字典和字典数组进行Swift JSON解析

您不能

return

添加这样的回调：

completion: (dictionary: NSDictionary) -> Void

解析器方法签名：

func jsonParserForDataUsage(urlFordata: String, completion: (dictionary: NSDictionary) -> Void)

并在您要“返回”的数据可用的地方调用补全：

func jsonParserForDataUsage(urlFordata: String, completion: (dictionary: NSDictionary) -> Void) {    print("json parser activated")    let urlPath = urlForData    guard let endpoint = NSURL(string: urlPath) else {        return    }    let request = NSMutableURLRequest(URL:endpoint)    NSURLSession.sharedSession().dataTaskWithRequest(request) { (data, response, error) -> Void in        do { guard let dat = data else {     throw JSONError.NoData } guard let dictionary = try NSJSONSerialization.JSonObjectWithData(dat, options:.AllowFragments) as? NSDictionary else {     throw JSONError.ConversionFailed } completion(dictionary: dictionary)        } catch let error as JSonError { print(error.rawValue)        } catch let error as NSError { print(error.debugDescription)        }    }.resume()}

现在，您可以将此方法与结尾的闭包一起使用，以获取“返回的”值：

jsonParserForDataUsage("http...") { (dictionary) in    print(dictionary)}