#include <iostream>#include <cmath>using namespace std;const int Y = 1960;int main(){ int year; double sum; while(cin >> year) { if(year == 0) break; int tmp = pow(2*1.0,(year - Y) / 10 + 2); int n = 2; sum = 0; while(sum <= tmp) { sum += log(n*1.0) / log(2*1.0); n++; } cout << n - 2 << endl; } return 0;}


