一个纯bash解决方案：
old=09:11new=17:22# feeding variables by using read and splitting with IFSIFS=: read old_hour old_min <<< "$old"IFS=: read hour min <<< "$new"# convert hours to minutes# the 10# is there to avoid errors with leading zeros# by telling bash that we use base 10total_old_minutes=$((10#$old_hour*60 + 10#$old_min))total_minutes=$((10#$hour*60 + 10#$min))echo "the difference is $((total_minutes - total_old_minutes)) minutes"
使用的另一种解决方案
date（我们使用小时/分钟，因此日期并不重要）
old=09:11new=17:22IFS=: read old_hour old_min <<< "$old"IFS=: read hour min <<< "$new"# convert the date "1970-01-01 hour:min:00" in seconds from Unix EPOCH timesec_old=$(date -d "1970-01-01 $old_hour:$old_min:00" +%s)sec_new=$(date -d "1970-01-01 $hour:$min:00" +%s)echo "the difference is $(( (sec_new - sec_old) / 60)) minutes"
参见http://en.wikipedia.org/wiki/Unix_time
