栏目分类:
子分类:
返回
名师互学网用户登录
快速导航关闭
当前搜索
当前分类
子分类
实用工具
热门搜索
名师互学网 > IT > 面试经验 > 面试问答

poj 3847 Moving to Nuremberg

面试问答 更新时间: 发布时间: IT归档 最新发布 模块sitemap 名妆网 法律咨询 聚返吧 英语巴士网 伯小乐 网商动力

poj 3847 Moving to Nuremberg

#include<stdio.h>#include<memory.h>#define N 50010#define oo 1000000000000000LLint n, m, num, cas, u, v, i, j;long long ans, sum, w;int head[N], nxt[N * 2], ev[N*2],temp[N];long long frequency[N], f[N], ew[N * 2], dp[N],dis[N];void addedge(int u, int v, long long w){    nxt[++num] = head[u];    head[u] = num;    ev[num] = v;    ew[num] = w;}void readin(){    memset(head, -1, sizeof(head));    memset(frequency, 0, sizeof(frequency));    num = -1;    scanf("%d", &n);    for (i = 0; i < n - 1; i++)    {        scanf("%d%d%lld", &u, &v, &w);        addedge(u, v, w);        addedge(v, u, w);    }    sum = 0;    scanf("%d", &m);    for (i = 0; i < m; i++)    {        scanf("%d%lld", &u, &w);        frequency[u] = w;        sum += frequency[u];    }}void pre_dfs(int father, int u){    int i;    f[u] = 0;    dis[u] = 0;    for (i = head[u]; i != -1; i = nxt[i])        if (ev[i] != father)        { pre_dfs(u, ev[i]); dis[u] += dis[ev[i]] + 2 * ew[i] * f[ev[i]]; f[u] += f[ev[i]];        }    f[u] += frequency[u];}void dfs(int father, int u, long long dis){    int i;    dp[u] = dis;    if (dp[u] < ans)        ans = dp[u];    for (i = head[u]; i != -1; i = nxt[i])        if (father != ev[i]) dfs(u, ev[i], dis + 2 * ew[i] * (sum - 2 * f[ev[i]]));}void solve(){    pre_dfs(1, 1);    ans = oo;    dfs(1, 1, dis[1]);    printf("%lldn", ans);    for (j = -1, i = 1; i <= n; i++)        if (dp[i] == ans) temp[++j] = i;    for (i = 0; i <= j; i++)        if (i != j) printf("%d ", temp[i]);        else printf("%dn", temp[i]);}int main(){    scanf("%d", &cas);    while (cas--)    {        readin();        solve();    }    return 0;}
转载请注明:文章转载自 www.mshxw.com
本文地址:https://www.mshxw.com/it/374303.html
我们一直用心在做
关于我们 文章归档 网站地图 联系我们

版权所有 (c)2021-2022 MSHXW.COM

ICP备案号:晋ICP备2021003244-6号