栏目分类:
子分类:
返回
名师互学网用户登录
快速导航关闭
当前搜索
当前分类
子分类
实用工具
热门搜索
名师互学网 > IT > 面试经验 > 面试问答

zoj 3859 Candies

面试问答 更新时间: 发布时间: IT归档 最新发布 模块sitemap 名妆网 法律咨询 聚返吧 英语巴士网 伯小乐 网商动力

zoj 3859 Candies

#include<cstdio>#include<cstdlib>#include<iostream>#include<cstring>#include<map>#include<set>#include<list>#include<stack>#include<algorithm>#include<queue>#include<vector>#include<time.h>#include<iomanip>#include<assert.h>using namespace std;const int maxn = 100015;int maxv[maxn];int n;int sumv[maxn];bool sure[maxn];void R(int i){    while(i+3 < n+1){        sure[i+3] = 1;        maxv[i+3] = sumv[i+2] - sumv[i+1] + maxv[i];        i = i+3;    }}void L(int i){    while(i-3 >=1){        sure[i-3] = 1;        maxv[i-3] = sumv[i-2] - (sumv[i-1] - maxv[i]);        i = i-3;    }}int main(){    while(scanf("%d",&n)!=EOF){        memset(maxv,0,sizeof(maxv));        memset(sure,0,sizeof(sure));        for(int i = 1; i < n+1;++i){ int a; scanf("%d",&a); maxv[i] = a; if(a>=0)sure[i] = 1;        }        for(int i = 1; i < n + 1;++i){ scanf("%d",&sumv[i]);        }        R(0);        L(n+1);        int pos = -1;        for(int i = 0;i<=n;++i){ if(maxv[i] >=0 && maxv[i+1] >=0) {sure[i] = 1;sure[i+1] = 1;pos = i;break;}        }        if(pos >= 0){ for(int j = pos + 2;j < n+1;++j){     maxv[j] = sumv[j-1] - maxv[j-1] - maxv[j-2];     sure[j] = 1; } for(int j = pos - 1;j>=1;--j){     maxv[j]  = sumv[j+1] - maxv[j+1] - maxv[j+2];     sure[j] = 1; }        }        for(int i = 0; i <= n+1;++i)if(maxv[i]>=0)sure[i] = 1;        int min1 = 0;        int min2 = 0;        if(!sure[1])maxv[1] = 0;        if(!sure[2])maxv[2] = 0;        for(int i = 4; i <= n;i+=3){ if(sure[i])continue; maxv[i] =maxv[i-3] - sumv[i-2] +sumv[i-1]; min1 = max(min1,-maxv[i]);        }        for(int i = 5; i <= n ;i+=3){ if(sure[i])continue; maxv[i] = maxv[i-3] - sumv[i-2] +sumv[i-1]; min2 = max(min2,-maxv[i]);        }        int m;        scanf("%d",&m);        while(m--){ int p; scanf("%d",&p); p++; if(sure[p])     printf("%dn",maxv[p]); else if(p%3 == 1){     printf("%dn",sumv[1] - min2 +maxv[p]); } else {     printf("%dn",sumv[1] - min1 + maxv[p]); }        }    }    return 0;}
转载请注明:文章转载自 www.mshxw.com
本文地址:https://www.mshxw.com/it/374282.html
我们一直用心在做
关于我们 文章归档 网站地图 联系我们

版权所有 (c)2021-2022 MSHXW.COM

ICP备案号:晋ICP备2021003244-6号