栏目分类:
子分类:
返回
名师互学网用户登录
快速导航关闭
当前搜索
当前分类
子分类
实用工具
热门搜索
名师互学网 > IT > 面试经验 > 面试问答

在Swift中返回实例类型

面试问答 更新时间: 发布时间: IT归档 最新发布 模块sitemap 名妆网 法律咨询 聚返吧 英语巴士网 伯小乐 网商动力

在Swift中返回实例类型

与在Swift的类扩展函数中使用’self’类似,您可以定义一个通用的辅助方法,该方法可以从调用上下文中推断出self的类型:

extension UIViewController{    class func instantiateFromStoryboard(storyboardName: String, storyboardId: String) -> Self    {        return instantiateFromStoryboardHelper(storyboardName, storyboardId: storyboardId)    }    private class func instantiateFromStoryboardHelper<T>(storyboardName: String, storyboardId: String) -> T    {        let storyboard = UIStoryboard(name: storyboardName, bundle: nil)        let controller = storyboard.instantiateViewControllerWithIdentifier(storyboardId) as! T        return controller    }}

然后

let vc = MyViewController.instantiateFromStoryboard("name", storyboardId: "id")

进行编译,并将类型推断为

MyViewController


Swift 3 更新

extension UIViewController{    class func instantiateFromStoryboard(storyboardName: String, storyboardId: String) -> Self    {        return instantiateFromStoryboardHelper(storyboardName: storyboardName, storyboardId: storyboardId)    }    private class func instantiateFromStoryboardHelper<T>(storyboardName: String, storyboardId: String) -> T    {        let storyboard = UIStoryboard(name: storyboardName, bundle: nil)        let controller = storyboard.instantiateViewController(withIdentifier: storyboardId) as! T        return controller    }}

另一种可能的解决方案,使用

unsafeDowncast

extension UIViewController{    class func instantiateFromStoryboard(storyboardName: String, storyboardId: String) -> Self    {        let storyboard = UIStoryboard(name: storyboardName, bundle: nil)        let controller = storyboard.instantiateViewController(withIdentifier: storyboardId)        return unsafeDowncast(controller, to: self)    }}


转载请注明:文章转载自 www.mshxw.com
本文地址:https://www.mshxw.com/it/372917.html
我们一直用心在做
关于我们 文章归档 网站地图 联系我们

版权所有 (c)2021-2022 MSHXW.COM

ICP备案号:晋ICP备2021003244-6号