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zoj 3402 Marble

面试问答 更新时间: 发布时间: IT归档 最新发布 模块sitemap 名妆网 法律咨询 聚返吧 英语巴士网 伯小乐 网商动力

zoj 3402 Marble

#include <cstdio>#include <vector>#include <string>#include <cstring>#include <utility>#include <algorithm>using namespace std;const int MAXN = 17;const int LCM = 4 * 3 * 5;int opidx[MAXN][MAXN];string act[100], act2[100];string op[MAXN][MAXN];void gao(int r, int c, int x, int y, int z, vector<pair<int, int> >& path, int& begin, int& end) {static int d[MAXN][MAXN][LCM];memset(d, 0xff, sizeof(d));path.clear();while (d[x][y][z] == -1) {d[x][y][z] = path.size();path.push_back(make_pair(x, y));switch (op[x][y][z]) {case 'N': --x; break;case 'W': --y; break;case 'S': ++x; break;case 'E': ++y; break;case 'D':  begin = path.size();  path.push_back(make_pair(-1, -1));  end = path.size();  return;}if (x < 0 || y < 0 || x >= r || y >= c) {begin = path.size();path.push_back(make_pair(-1, -1));end = path.size();return;}++z;if (z == LCM) {z = 0;}}begin = d[x][y][z];end = path.size();}int begin[MAXN][MAXN][LCM], end[MAXN][MAXN][LCM];vector<pair<int, int> > path[MAXN][MAXN][LCM];inline pair<int, int> whereis(int x, int y, int z, long long t) {if (t < end[x][y][z]) {return path[x][y][z][t];} else {return path[x][y][z][begin[x][y][z] + (t - begin[x][y][z]) % (end[x][y][z] - begin[x][y][z])];}}long long val[MAXN][MAXN];int main() {int r, c, n;long long t, p, ans;pair<int, int> xy;static char buf[80];while (scanf("%d%d%lld%d", &r, &c, &t, &n) != EOF) {for (int i = 0; i < r; ++i) {for (int j = 0; j < c; ++j) {scanf("%1d", &opidx[i][j]);}}for (int i = 0; i < n; ++i) {scanf("%s", buf);act[i] = buf;act2[i] = "";while ((int)act2[i].length() != LCM) {act2[i] += act[i];}}for (int i = 0; i < r; ++i) {for (int j = 0; j < c; ++j) {op[i][j] = act2[opidx[i][j]];}}for (int i = 0; i < r; ++i) {for (int j = 0; j < c; ++j) {for (int k = 0; k < LCM; ++k) {gao(r, c, i, j, k, path[i][j][k], begin[i][j][k], end[i][j][k]);}}}memset(val, 0, sizeof(val));p = max(0LL, (t - MAXN * MAXN * LCM) / LCM - 1);for (int i = 0; i < r; ++i) {for (int j = 0; j < c; ++j) {if (p > 0) {for (int k = 0; k < LCM; ++k) {if (!('1' <= op[i][j][k % LCM] && op[i][j][k % LCM] <= '9')) {continue;}xy = whereis(i, j, k, t - k);if (xy != make_pair(-1, -1)) {val[xy.first][xy.second] += p * (op[i][j][k % LCM] - '0');}}}for (int k = p * LCM; k < t; ++k) {if (!('1' <= op[i][j][k % LCM] && op[i][j][k % LCM] <= '9')) {continue;}xy = whereis(i, j, k % LCM, t - k);if (xy != make_pair(-1, -1)) {val[xy.first][xy.second] += op[i][j][k % LCM] - '0';}}}}ans = 0;for (int i = 0; i < r; ++i) {for (int j = 0; j < c; ++j) {ans = max(ans, val[i][j]);}}printf("%lldn", ans);}}
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