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Java实现的JSON到XML的转换

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Java实现的JSON到XML的转换

不是Java,而是 纯XSLT 2.0实现

看一看在

f:json-document()
FXSL
2.x库

使用此功能非常容易合并JSon并将其用作XML。

例如,可以只编写以下XPath表达式:

f:json-document($vstrParam)/Students/*[sex = 'Female']

让所有的孩子

Students
sex = 'Female'

这是完整的示例:

<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:f="http://fxsl.sf.net/" exclude-result-prefixes="f xs" > <xsl:import href="../f/func-json-document.xsl"/> <xsl:output omit-xml-declaration="yes" indent="yes"/> <xsl:variable name="vstrParam" as="xs:string">{  "teacher":{    "name":      "Mr Borat",    "age":      "35",    "Nationality":      "Kazakhstan"  },  "Class":{    "Semester":      "Summer",    "Room":      null,    "Subject":      "Politics",    "Notes":      "We're happy, you happy?"},  "Students":    {      "Smith":        {"First Name":"Mary","sex":"Female"},      "Brown":        {"First Name":"John","sex":"Male"},      "Jackson":        {"First Name":"Jackie","sex":"Female"}    }    ,  "Grades":    {      "Test":      [        {"grade":"A","points":68,"grade":"B","points":25,"grade":"C","points":15},        {"grade":"C","points":2, "grade":"B","points":29, "grade":"A","points":55},        {"grade":"C","points":2, "grade":"A","points":72, "grade":"A","points":65}       ]    }} </xsl:variable> <xsl:template match="/">    <xsl:sequence select=     "f:json-document($vstrParam)/Students/*[sex = 'Female']"/> </xsl:template></xsl:stylesheet>

当上述转换应用于任何XML文档(忽略)时,将产生正确的结果

<Smith>   <First_Name>Mary</First_Name>   <sex>Female</sex></Smith><Jackson>   <First_Name>Jackie</First_Name>   <sex>Female</sex></Jackson>


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