进行jquery + ajax + php的最佳方法如下：
jQuery的：
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script><script type="text/javascript">function do_ajax() { //set data var myData = new Array(); myData.push({name:'deletearray',value:'deletearray'}); myData.push({name:'dir',value:'dir'}); //ajax post $.ajax({ dataType: 'json', url: 'delete.php', type: 'post', data: myData, success: function(returnData) { if(returnData.undeleted == 0) { alert('All ' + returnData.deleted + ' files delted from the server'); } else { alert(returnData.deleted + ' files deleted and ' + returnData.undeleted + ' files could not be deleted'); } } });} </script>PHP：
<?php $myData = $_POST; if(isset($myData['deletearray']) AND isset($myData['dir'])) { $files = $myData['deletearray']; $dir = $myData['dir']; $deleted = 0; $undeleted = 0; foreach($files as $file) { if(unlink($dir.$file) && unlink($dir.'thumb/'.$file)) { $deleted ++; } else { $undeleted ++; } } print(json_enpre(array('deleted' => $deleted, 'undeleted' => $undeleted))); exit(); }?>
