如何在不使用DefaultServeMux的情况下实现HandlerFunc

将您的授权中间件重新实现为

http.Handler

type auth struct {   DB *sql.DB   UnauthorizedHandler http.Handler}func NewAuth(db *sql.DB, unauthorized http.Handler) *auth {    return auth{db, unauthorized}}func (a *auth) Protected(h http.Handler) http.Handler {    fn := func(w http.ResponseWriter, r *http.Request) {        // Check whether the request is valid        // If it's invalid, call your error func and make sure to *return* early!        if !valid { a.UnauthorizedHandler.ServeHTTP(w, r) return        }        // Call the next handler on success        h.ServeHTTP(w, r)        return    }    return http.HandlerFunc(fn)}func someHandler(w http.ResponseWriter, r *http.Request) {    io.WriteString(w, "Hello!n")}func main() {    auth := NewAuth(db, errorHandler)    r := http.NewServeMux()    // We have a http.Handler implementation that wraps a http.HandlerFunc    // ... so we call r.Handle on our ServeMux and type-cast the wrapped func    r.Handle("/protected", auth.Protected(http.HandlerFunc(someHandler)))    // Just a simple http.HandlerFunc here    r.HandleFunc("/public", someOtherHandler)    log.Fatal(http.ListenAndServe(":8000", r))}

Take a look at the httpauth lib I
wrote
for a
different example with a

ServeHTTP

ServeHTTP