Swift 2

这应该起作用：将对象指针作为不透明的非托管指针传递给回调：

context.info = UnsafeMutablePointer(Unmanaged.passUnretained(myObject).toOpaque())SCNetworkReachabilitySetCallback(reachability, callback, &context)

并通过以下方式检索回调：

func callback(reachability:SCNetworkReachability, flags: SCNetworkReachabilityFlags, info: UnsafeMutablePointer<Void>) {    let myObject = Unmanaged<MyObject>.fromOpaque(COpaquePointer(info)).takeUnretainedValue()}

当然，这假定只要安装了回调，就存在对该对象的某些强引用，因此不会释放该对象。

更新： 请注意，如果您愿意使用“不安全”功能，则可以简化从对象指针到void指针以及返回的转换：

context.info = unsafeAddressOf(myObject)// ...myObject = unsafeBitCast(info, MyObject.self)

据我所知，生成的汇编代码是相同的。

更新2： 另请参阅如何快速将自身转换为UnsafeMutablePointer

<Void>

Swift 3更新（Xpre 8 beta 6）：

var context = SCNetworkReachabilityContext(version: 0, info: nil, retain: nil, release: nil, copyDescription: nil)context.info = UnsafeMutableRawPointer(Unmanaged.passUnretained(self).toOpaque())// ...func callback(reachability:SCNetworkReachability, flags: SCNetworkReachabilityFlags, info: UnsafeMutableRawPointer?) {    if let info = info {        let myObject = Unmanaged<MyObject>.fromOpaque(info).takeUnretainedValue()        // ...    }}