具有许多属性的Spring Data JPA中过滤结果的最佳解决方案是什么？

我不同意QueryDSL会导致大量额外的代码。这是QueryDSL的一些测试代码：

仓库定义：

public interface UserRepository extends PagingAndSortingRepository<User, Long>, QueryDslPredicateExecutor<User> {    public User findOne(Predicate predicate);    public List<User> findAll(Predicate predicate);}

基于各种属性及其组合的测试代码：

 @Test    public void testFindByEmailAddress() {        User user = repository.findOne(QUser.user.emailAddress.eq("jack@hamilton.net"));        Assert.assertNotNull(user);        Assert.assertEquals("Jack", user.getForename());        Assert.assertEquals("Hamilton", user.getSurname());    }    @Test    public void testFindByGender() {        List<User> users = repository.findAll(QUser.user.gender.eq(Gender.M));        Assert.assertEquals(4, users.size());        users = repository.findAll(QUser.user.gender.eq(Gender.F));        Assert.assertEquals(2, users.size());    }    @Test    public void testFindByCity() {        List<User> users = repository.findAll(QUser.user.address.town.eq("Edinburgh"));        Assert.assertEquals(2, users.size());        users = repository.findAll(QUser.user.address.town.eq("Stirling"));        Assert.assertEquals(1, users.size());    }    @Test    public void testFindByGenderAndCity() {        List<User> users = repository.findAll(QUser.user.address.town.eq("Glasgow").and(QUser.user.gender.eq(Gender.M)));        Assert.assertEquals(2, users.size());        users = repository.findAll(QUser.user.address.town.eq("Glasgow").and(QUser.user.gender.eq(Gender.F)));        Assert.assertEquals(1, users.size());    }