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poj 1831 不定方程组

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poj 1831 不定方程组

#include<iostream>#include<sstream>#include<fstream>#include<vector>#include<list>#include<deque>#include<queue>#include<stack>#include<map>#include<set>#include<bitset>#include<algorithm>#include<cstdio>#include<cstdlib>#include<cstring>#include<cctype>#include<cmath>#include<ctime>#include<utility>#define M0(x) memset(x, 0, sizeof(x))#define Inf 0x7fffffff#define PB push_back#define SZ(v) ((int)(v).size())#define N 76666using namespace std;int n, m, T, ans[N];bool dfs(int k, int s){    if (s > n) return false;    int r, w;    if (s == n){         m = k;         return true;    }    for (int i = 1; i <= k; ++i){         r = ans[i];         ans[i] = r + 1;         ans[k+1] = r * (r + 1);         if (dfs(k + 1, s + r * r + r + 1)) return true;         w = 4;         for (int j = 2; j <= w; ++j){   ans[i] = r * j;   for (int t = 1; t < j; ++t) ans[k + t] = r * j;   if (dfs(k + j - 1, s + (j * j - 1) * r)) return true;         }         ans[i] = r;    }    return false;}void solve(){    scanf("%d", &n);    int r = int(sqrt(n + .0));    if (r * r == n){        for (int i = 0; i <= r; ++i) printf("%d ", r);        puts("");        return;    }    if (n == 32){ printf ("4 2 3 9 18n") ; return;    }    if (n == 39){ printf ("5 2 6 6 10 15n") ; return ;    }    ans[1] = 1 ;    if (dfs(1, 1)){         printf("%d ", m);         for (int i = 1; i <= m; ++i)  printf("%d ", ans[i]);         puts("");    } else puts("-1");}int main(){    scanf("%d", &T);    for (int i = 1; i <= T; ++i){          solve();    }    return 0;}
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