一种选择是使用排名变量，例如：
SELECt first_name, age, gender, @curRank := @curRank + 1 AS rankFROM person p, (SELECT @curRank := 0) rORDER BY age;
该
(SELECT @curRank := 0)部分允许变量初始化，而无需单独的
SET命令。
测试用例：
CREATE TABLE person (id int, first_name varchar(20), age int, gender char(1));INSERT INTO person VALUES (1, 'Bob', 25, 'M');INSERT INTO person VALUES (2, 'Jane', 20, 'F');INSERT INTO person VALUES (3, 'Jack', 30, 'M');INSERT INTO person VALUES (4, 'Bill', 32, 'M');INSERT INTO person VALUES (5, 'Nick', 22, 'M');INSERT INTO person VALUES (6, 'Kathy', 18, 'F');INSERT INTO person VALUES (7, 'Steve', 36, 'M');INSERT INTO person VALUES (8, 'Anne', 25, 'F');
结果：
+------------+------+--------+------+| first_name | age | gender | rank |+------------+------+--------+------+| Kathy | 18 | F | 1 || Jane | 20 | F | 2 || Nick | 22 | M | 3 || Bob | 25 | M | 4 || Anne | 25 | F | 5 || Jack | 30 | M | 6 || Bill | 32 | M | 7 || Steve | 36 | M | 8 |+------------+------+--------+------+8 rows in set (0.02 sec)
