poj 2109 Power of Cryptography

#include<stdio.h>#include<math.h>#define eps 0.0000000001void init(), work();double n, m, k;int main(){    init();    return 0;}void init(){    while(scanf("%lf %lf", &n, &m) != EOF)        work();}void work(){    long long left, right, mid;    left = 0;    right = 1000000002;    while(left + eps < right){        mid = (left + right) / 2;        if(pow(mid, n) - m > 0) right = mid;        else if(pow(mid, n) - m < 0)     left = mid; else{     printf("%.0ldn", mid) ;     break; }    }}