参考回答:
long long Fib(long long N){long long first = 1;long long second = 1;long long ret = 0;for (int i = 3; i <=N; ++i){ret = first + second;first = second;second = ret;}return second;}
参考回答:
long long Fib(long long N){long long first = 1;long long second = 1;long long ret = 0;for (int i = 3; i <=N; ++i){ret = first + second;first = second;second = ret;}return second;}