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spring快速入门

Java 更新时间: 发布时间: IT归档 最新发布 模块sitemap 名妆网 法律咨询 聚返吧 英语巴士网 伯小乐 网商动力

spring快速入门

流程 1、导入依赖
 
    
        org.springframework
        spring-webmvc
        5.3.3
    
2、创建实体类
package pojo;

public class Teacher {
    private String name;
    private Integer age;

    public Teacher() {
    }

    public Teacher(String name, Integer age) {
        this.name = name;
        this.age = age;
    }

    public void setName(String name) {
        this.name = name;
    }

    public void setAge(Integer age) {
        this.age = age;
    }

    @Override
    public String toString() {
        return "Teacher{" +
                "name='" + name + ''' +
                ", age=" + age +
                '}';
    }
}
3、配置spring配置文件



    
        
        
    

4、测试
@Test
    public void test1(){
        //ClassPathXmlApplicationContext:用于加载spring配置文件到spring容器中进行bean的初始化
        ApplicationContext context = new ClassPathXmlApplicationContext("bean.xml");
        //getBean():可以通过配置文件中的id进行查找,并返回对应的结果
        Teacher teacher1 = context.getBean("teacher1", Teacher.class);
        System.out.println(teacher1);
    }
    
5、优化

关于如果存在嵌套的话,就如下例:

Student中又有Teacher类的引用

package pojo;

import org.springframework.context.annotation.ComponentScan;
import org.springframework.stereotype.Component;

@Component
public class Student {
    private String name;
    private Integer age;
    private Teacher teacher;

    public Student() {
    }

    public void setTeacher(Teacher teacher) {
        this.teacher = teacher;
    }

    public Student(String name, Integer age) {
        this.name = name;
        this.age = age;
    }

    public void setName(String name) {
        this.name = name;
    }

    public void setAge(Integer age) {
        this.age = age;
    }

    @Override
    public String toString() {
        return "Student{" +
                "name='" + name + ''' +
                ", age=" + age +
                ", teacher=" + teacher +
                '}';
    }
}

对应的解决方法

1、



    
        
        
        
            
                
                
            
        
    

2、




    
        
        
    
    
        
        
        
    


测试

@Test
public void test2(){
    ApplicationContext context = new ClassPathXmlApplicationContext("bean.xml");
    Student student = context.getBean("student", Student.class);
    System.out.println(student);
}

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