关于java中列表数据如何优雅删除

	public void delList() {
		//生成一个Member列表集合
		List members = new ArrayList<>();
		//向集合中添加5个对象
		for (long i = 1; i < 5; i++) {
			Member member = new Member();
			member.setId(i);
			members.add(member);
		}
		//删除id为1的Member对象
		

		
		for (Member member : members) {
			if (member.getId() == 1) {
				members.remove(member);
			}
		}
		 
		for (int i = 0; i < members.size(); i++) {
			Member member = members.get(i);
			if (member.getId() == 1) {
				members.remove(member);
				//删除之后可以添加break直接跳出可以解决 java.util.ConcurrentModificationException 异常 但是不在向下循环了
				//break;
			}
		}
		//打印
		members.forEach(item -> {
			System.out.println(item);
		});
		

		//不建议
		
		for (int i = members.size() - 1; i >= 0; i--) {
			if (1 == members.get(i).getId()) {
				members.remove(i);
			}
		}
		//建议  使用迭代器的方式正确无误的删除
		Iterator iterator = members.iterator();
		while (iterator.hasNext()) {
			if (iterator.next().getId() == 1) {
				iterator.remove();
			}
		}

		//打印
		members.forEach(item -> {
			System.out.println(item);
		});
	}