栏目分类:
子分类:
返回
名师互学网用户登录
快速导航关闭
当前搜索
当前分类
子分类
实用工具
热门搜索
名师互学网 > IT > 软件开发 > 后端开发 > Python

python random.sample

Python 更新时间: 发布时间: IT归档 最新发布 模块sitemap 名妆网 法律咨询 聚返吧 英语巴士网 伯小乐 网商动力

python random.sample

random.sample 从集合或者序列中,无放回采样

用法:

sample_list=random.sample(population, k)
# population : 可以是一个集合,也可以是序列(list,tuple,或者字符串)
# k : 0<= k<= len(population) 
# 返回一个list,如果是字符串的话,返回的是['index1','index2']随机选择的索引值
# 注意:不会改变原来的 population

测试:

import random

random.seed(66)
a1=list(range(0,10))
print(a1,type(a1))
b1= random.sample(a1,2)
print(b1)
print(a1)
"""
结果:
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9] 
[1, 4]
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
"""

a2=tuple(range(0,10))
print(a2,type(a2))
b2= random.sample(a2,2)
print(b2)
print(a2)
"""
结果:
(0, 1, 2, 3, 4, 5, 6, 7, 8, 9) 
[6, 3]
(0, 1, 2, 3, 4, 5, 6, 7, 8, 9)
"""

a3='1234567890'
print(a3,type(a3))
b3= random.sample(a3,2)
print(b3)
print(a3)
"""
结果:
1234567890 
['8', '5']
1234567890
"""

a4=dict(spam = 1, egg = 2, bar =3)
print(a4,type(a4))
b4= random.sample(a4,2)
print(b4)
print(a4)
# 报错:不能处理dict

a5 = set(("Google", "Runoob", "Taobao"))
print(a5,type(a5))
b5= random.sample(a5,2)
print(b5)
print(a5)
"""
结果:
{'Runoob', 'Taobao', 'Google'} 
['Taobao', 'Runoob']
{'Runoob', 'Taobao', 'Google'}
"""

源代码:

    def sample(self, population, k):
        """Chooses k unique random elements from a population sequence or set.

        Returns a new list containing elements from the population while
        leaving the original population unchanged.  The resulting list is
        in selection order so that all sub-slices will also be valid random
        samples.  This allows raffle winners (the sample) to be partitioned
        into grand prize and second place winners (the subslices).

        Members of the population need not be hashable or unique.  If the
        population contains repeats, then each occurrence is a possible
        selection in the sample.

        To choose a sample in a range of integers, use range as an argument.
        This is especially fast and space efficient for sampling from a
        large population:   sample(range(10000000), 60)
        """

        # Sampling without replacement entails tracking either potential
        # selections (the pool) in a list or previous selections in a set.

        # When the number of selections is small compared to the
        # population, then tracking selections is efficient, requiring
        # only a small set and an occasional reselection.  For
        # a larger number of selections, the pool tracking method is
        # preferred since the list takes less space than the
        # set and it doesn't suffer from frequent reselections.

        if isinstance(population, _Set):
            population = tuple(population)
        if not isinstance(population, _Sequence):
            raise TypeError("Population must be a sequence or set.  For dicts, use list(d).")
        randbelow = self._randbelow
        n = len(population)
        if not 0 <= k <= n:
            raise ValueError("Sample larger than population or is negative")
        result = [None] * k
        setsize = 21        # size of a small set minus size of an empty list
        if k > 5:
            setsize += 4 ** _ceil(_log(k * 3, 4)) # table size for big sets
        if n <= setsize:
            # An n-length list is smaller than a k-length set
            pool = list(population)
            for i in range(k):         # invariant:  non-selected at [0,n-i)
                j = randbelow(n-i)
                result[i] = pool[j]
                pool[j] = pool[n-i-1]   # move non-selected item into vacancy
        else:
            selected = set()
            selected_add = selected.add
            for i in range(k):
                j = randbelow(n)
                while j in selected:
                    j = randbelow(n)
                selected_add(j)
                result[i] = population[j]
        return result
转载请注明:文章转载自 www.mshxw.com
本文地址:https://www.mshxw.com/it/355677.html
我们一直用心在做
关于我们 文章归档 网站地图 联系我们

版权所有 (c)2021-2022 MSHXW.COM

ICP备案号:晋ICP备2021003244-6号