用python控制大华摄像头简单转动

        控制摄像头的代码

import socket
import time


class Control:

    def left(self,i):
        client = socket.socket()
        client.connect(('192.168.1.64', 8100))
        client.send(b'x00x00x00x00x00x00x22x31x00x03x17x00x08')
        # 先补6个0，命令一，命令二，数据长度（两位），左转，状态（开始/停止），速度
        time.sleep(i)
        print('左转',i)
        client.close()


    def right(self,i):
        client = socket.socket()
        client.connect(('192.168.1.64', 8100))
        client.send(b'x00x00x00x00x00x00x22x31x00x03x18x00x04')
        time.sleep(i)
        print('右转',i)
        client.close()


    def stop(self,i):

        client = socket.socket()
        client.connect(('192.168.1.64', 8100))
        client.send(b'x00x00x00x00x00x00x22x31x00x03x17x01x04')
        time.sleep(i)
        print('停转',i)
        client.close()

        调用控制程序转动一定角度

        设了一个假目标，目标距离小于500摄像头就转动，转动方位自定义输入。假设电机转速为每秒30°

import cmath
import math

import numpy as np
from numpy import loadtxt
from control import Control


x = 300
y = float(input('输入方位：'))

if x < 500:
    i = y/30
    print('应转',i)
    # 左转
    if y < 0 :
        Control().left(-i)
    # 右转
    elif y > 0:
        Control().right(i)
    # 原点
    else:
        Control().stop(i)

        运行结果

输入方位：30
应转 1.0
右转 1.0