写了一个看了虎躯一震的代码
题目为：
（1）求出它是几位数；
（2）分别输出每一位数字；
（3）按逆序输出每位数字，例如原数为 321，应输出 123。
下面贴上源代码（python）
import math
number=int(input("请输入一个不多于5位的正整数："))
digit=0;
number_1=0
number_2=0
number_3=0
number_4=0
number_5=0
if number>=10000:
digit=5
number_5=math.floor(number/10000)
number_4=math.floor(number/1000)-number_5*10
number_3=math.floor(number/100)-number_5*100-number_4*10
number_2=math.floor(number/10)-number_5*1000-number_4*100-number_3*10
number_1=math.floor(number/1)-number_5*10000-number_4*1000-number_3*100-number_2*10
elif number>=1000:
digit=4
number_4=math.floor(number/1000)
number_3=math.floor(number/100)-number_4*10
number_2=math.floor(number/10)-number_4*100-number_3*10
number_1=math.floor(number/1)-number_4*1000-number_3*100-number_2*10
elif number>=100:
digit=3
number_3=math.floor(number/100)
number_2=math.floor(number/10)-number_3*10
number_1=math.floor(number/1)-number_3*100-number_2*10
elif number>=10:
digit=2
number_2=math.floor(number/10)
number_1=math.floor(number/1)-number_2*10
elif number>=0:
digit=1
number_1=math.floor(number/1)
print(str(number)+"是一个"+str(digit)+"位数")
if number_5!=0:
print("万位数字为："+str(number_5))
if number_4!=0:
print("千位数字为："+str(number_4))
if number_3!=0:
print("百位数字为："+str(number_3))
if number_2!=0:
print("十位数字为："+str(number_2))
if number_1!=0:
print("个位数字为："+str(number_1))
print("逆序输出为：")
if digit==1:
print(str(number_1))
elif digit==2:
print(str(number_1)+str(number_2))
elif digit==3:
print(str(number_1)+str(number_2)+str(number_3))
elif digit==4:
print(str(number_1)+str(number_2)+str(number_3)+str(number_4))
elif digit==5:
print(str(number_1)+str(number_2)+str(number_3)+str(number_4)+str(number_5))
运行结果当然也相当的nice:
