linkkk
题意： 思路：模拟，数太大了可以用java或py写，记录一下大数的输入和 A P I API API
代码：
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n.compareTo
n.compareTo表示和某个数比较
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BigInteger.valueOf
BigInteger.valueOf表示将某个数转为大数
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(
"
−
9223372036854775808
"
)
new BigInteger("-9223372036854775808")
newBigInteger("−9223372036854775808")表示将字符串变为大数
import java.math.BigInteger;
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
BigInteger n=sc.nextBigInteger();
if(n.compareTo(BigInteger.valueOf(-128))>=0&&n.compareTo(BigInteger.valueOf(127))<=0)
System.out.println("byte");
else if(n.compareTo(BigInteger.valueOf(-32768))>=0&&n.compareTo(BigInteger.valueOf(32767))<=0)
System.out.println("short");
else if(n.compareTo(BigInteger.valueOf(-2147483648))>=0&&n.compareTo(BigInteger.valueOf(2147483647))<=0)
System.out.println("int");
else if(n.compareTo(new BigInteger("-9223372036854775808"))>=0&&n.compareTo(new BigInteger("9223372036854775807"))<=0)
System.out.println("long");
else
System.out.println("BigInteger");
}
}
n=int(input())
if -128<=n<=127:
print("byte")
elif -32768<=n<=32767:
print("short")
elif -2147483648<=n<=2147483647:
print("int")
elif -9223372036854775808<=n<=9223372036854775807:
print("long")
else:
print("BigInteger")
