python for 循环中使用星号(*)，实现分组展开列表

import numpy as np

a = np.random.uniform(0, 1, (5, 6))

print(a)

for *b, c, d in a:
    print(b, c, d)

for b, c, *d in a:
    print(b, c, d)

三个print的结果如下：

[[2.59082666e-01 9.33421608e-02 3.14394861e-01 5.21211733e-01
  1.45397325e-01 9.50105984e-04]
 [1.06471904e-01 2.08233001e-01 9.45687573e-01 4.77635986e-01
  1.15698356e-01 8.77691012e-01]
 [2.67165641e-01 9.69817760e-01 1.90024148e-02 4.34003087e-01
  3.78529636e-01 7.91454564e-01]
 [5.45704983e-01 5.27884108e-01 2.68554314e-01 2.31240267e-03
  3.58575802e-02 3.29896612e-01]
 [2.69259422e-01 6.62100724e-01 2.30178897e-01 4.78810788e-02
  2.58792575e-02 9.19565646e-01]]

 [0.259082665748668, 0.0933421607590641, 0.31439486129202887, 0.521211733137794] 0.14539732546645678 0.0009501059838643577
[0.10647190379252569, 0.20823300141803736, 0.9456875734737963, 0.47763598619698655] 0.11569835557059593 0.8776910120723697
[0.2671656406671584, 0.9698177601248633, 0.01900241482557319, 0.4340030873165195] 0.3785296355936244 0.7914545642238436
[0.5457049827172322, 0.5278841077140354, 0.2685543140893826, 0.002312402674624514] 0.03585758021822538 0.3298966119945801
[0.269259422244588, 0.6621007242460392, 0.2301788971051998, 0.047881078848715286] 0.02587925750136999 0.9195656458937822

 0.259082665748668 0.0933421607590641 [0.31439486129202887, 0.521211733137794, 0.14539732546645678, 0.0009501059838643577]
0.10647190379252569 0.20823300141803736 [0.9456875734737963, 0.47763598619698655, 0.11569835557059593, 0.8776910120723697]
0.2671656406671584 0.9698177601248633 [0.01900241482557319, 0.4340030873165195, 0.3785296355936244, 0.7914545642238436]
0.5457049827172322 0.5278841077140354 [0.2685543140893826, 0.002312402674624514, 0.03585758021822538, 0.3298966119945801]
0.269259422244588 0.6621007242460392 [0.2301788971051998, 0.047881078848715286, 0.02587925750136999, 0.9195656458937822]