991 有序插入
#include
using namespace std;
const int N = 109;
int n, a[N];
int main() {
cin >> n;
for (int i = 1; i <= n; i ++) cin >> a[i];
cin >> a[++n];
int k = n;
while (a[k] > a[k-1] && k >= 2) {
swap(a[k], a[k-1]);
k --;
}
for (int i = 1; i <= n; i ++) cout << a[i] << ' ';
return 0;
}
992 插队
#include
using namespace std;
const int N = 109;
int n, x, a[N];
int main() {
cin >> n;
for (int i = 1; i <= n; i ++) {
cin >> a[i];
if (a[i] + a[i-1] > 350) {
cout << 50 << ' ';
}
cout << a[i] << ' ';
}
return 0;
}
993 删除数组中重复的数
#include
using namespace std;
int n, x;
set s;
set :: iterator it;
int main() {
cin >> n;
for (int i = 1; i <= n; i ++) {
cin >> x;
s.insert(x);
}
for (it = s.begin(); it != s.end(); it ++) cout << *it << ' ';
return 0;
}
994 删除倍数
#include
using namespace std;
const int N = 109;
int n, x, a[N];
int main() {
cin >> n >> x;
for (int i = 1; i <= n; i ++) {
cin >> a[i];
if (a[i] % x != 0) {
cout << a[i] << ' ';
}
}
return 0;
}
995 第K个点
#include
using namespace std;
const int N = 1009;
int n, k, x;
set s;
set :: iterator it;
int main() {
cin >> n >> k;
for (int i = 1; i <= n; i ++) {
cin >> x;
s.insert(x);
}
it = s.begin();
for (int i = 1; i < k; i ++) it ++;
cout << *it << endl;
return 0;
}
996 前缀和
#include
using namespace std;
const int N = 109;
int n, a[N], b[N];
int main() {
cin >> n;
for (int i = 1; i <= n; i ++) {
cin >> a[i];
b[i] = b[i-1] + a[i];
cout << b[i] << ' ';
}
return 0;
}
997 前缀和的逆
#include
using namespace std;
const int N = 109;
int n, a[N], b[N];
int main() {
cin >> n;
for (int i = 1; i <= n; i ++) {
cin >> b[i];
a[i] = b[i] - b[i-1];
cout << a[i] << ' ';
}
return 0;
}
998 新数列
#include
using namespace std;
const int N = 109;
int n, a[N], b[N];
int main() {
cin >> n;
for (int i = 1; i <= n; i ++) cin >> a[i];
for (int i = 1; i <= n; i ++) {
if (i == 1 || i == n) cout << a[i] << ' ';
else cout << a[i-1] + a[i] + a[i+1] << ' ';
}
return 0;
}
999 多次求一段和
#include
using namespace std;
const int N = 1e5 + 10;
int n, m, a[N], s[N];
int main() {
scanf("%d%d", &n, &m);
for (int i = 1; i <= n; i ++) {
scanf("%d", &a[i]);
s[i] = s[i-1] + a[i];
}
while (m --) {
int x, y;
scanf("%d%d", &x, &y);
if (x > y) swap(x, y);
printf("%dn", s[y] - s[x - 1]);
}
return 0;
}
1000 11的倍数
#include
using namespace std;
const int N = 1e5 + 10;
int n, m, a[N], s[N];
int main() {
scanf("%d%d", &n, &m);
for (int i = 1; i <= n; i ++) {
scanf("%d", &a[i]);
s[i] = s[i-1] + a[i];
}
while (m --) {
int x, y;
scanf("%d%d", &x, &y);
if (x > y) swap(x, y);
int t = s[y] - s[x - 1];
if (t % 11 == 0) puts("1");
else puts("0");
}
return 0;
}
1001鸡蛋
#include
using namespace std;
const int N = 1e5 + 10;
int n, a[N], s[N], h[7];
int main() {
scanf("%d", &n);
for (int i = 1; i <= n; i ++) {
scanf("%d", &a[i]);
s[i] = s[i-1] + a[i];
h[s[i] % 7] ++;
}
long long ans = h[0];
for (int i = 0; i < 7; i ++) {
ans += h[i] * (h[i] - 1) / 2;
}
cout << ans;
return 0;
}