OpenCV学习(2)-矩阵运算

# -*- coding:utf-8 -*-
import numpy as np
import cv2

if __name__ == "__main__":
   src1=np.array([[23,123,90],[100,250,0]],np.uint8)
   src2=np.array([[125,150,60],[100,10,40]],np.float32)
   dst=src1+src2
   print('+:',dst)
   dst=cv2.add(src1,src2,dtype=cv2.CV_32F)
   print('+:',dst)
   dst=src1-src2
   print('-:',dst)#uint8下-102会显示成-102+255+1=154
   
   dst=src1*src2
   print('*:',dst)
   dst=np.multiply(src1,src2)
   print('*:',dst)
   dst=src1/src2
   print('/:',dst)
   
   src3=np.array([[125,150],[100,10],[2,2]],np.float32)
   dst=np.dot(src1,src3)
   print('dot:',dst)
   
   dst=np.log([[2,3],[4,9]])
   print('log:',dst)
   dst=np.exp([[1,2,4],[8,6,3]])
   print('exp:',dst)
   
   dst=np.power(src1,2)
   print('power:',dst)#有精度损失
   dst=np.power(src1,2.0)
   print('power:',dst)
   
   dst=np.sqrt(src1)
   print('sqrt:',dst)
   
'''
result:
+: [[148. 273. 150.]
 [200. 260.  40.]]
+: [[148. 273. 150.]
 [200. 260.  40.]]
-: [[-102.  -27.   30.]
 [   0.  240.  -40.]]
 
*: [[ 2875. 18450.  5400.]
 [10000.  2500.     0.]]
*: [[ 2875. 18450.  5400.]
 [10000.  2500.     0.]]
/: [[ 0.184  0.82   1.5  ]
 [ 1.    25.     0.   ]]
 
dot: [[15355.  4860.]
 [37500. 17500.]]
 
log: [[0.69314718 1.09861229]
 [1.38629436 2.19722458]]
exp: [[2.71828183e+00 7.38905610e+00 5.45981500e+01]
 [2.98095799e+03 4.03428793e+02 2.00855369e+01]]
 
power: [[ 17  25 164]
 [ 16  36   0]]
power: [[  529. 15129.  8100.]
 [10000. 62500.     0.]]
 
sqrt: [[ 4.797 11.09   9.484]
 [10.    15.81   0.   ]]

'''