30以内阶乘

public class TestJieCheng {

    public static void jiecheng(int n) {

        int result = 1;

        while(n > 1){
            result *= n * (n - 1);
            n -= 2;
        }
        System.out.println("n的阶乘为：" + result);
    }

    public static void main(String[] args) {
        jiecheng(10);
    }
}