- 题目描述
- 思路分析
- 代码实现
点这里
思路分析暴力枚举
在思路上,和三数之和没什么区别
class Solution {
public:
vector> fourSum(vector& nums, int target) {
sort(nums.begin(), nums.end());
vector> res;
for (int i = 0; i < nums.size(); i ++ ) {
if (i && nums[i] == nums[i - 1]) continue;
for (int j = i + 1; j < nums.size(); j ++ ) {
if (j > i + 1 && nums[j] == nums[j - 1]) continue;
for (int k = j + 1, u = nums.size() - 1; k < u; k ++ ) {
if (k > j + 1 && nums[k] == nums[k - 1]) continue;
while (u - 1 > k && (long long)nums[i] + nums[j] + nums[k] + nums[u - 1] >= target) u -- ;
if ((long long)nums[i] + nums[j] + nums[k] + nums[u] == target) {
res.push_back({nums[i], nums[j], nums[k], nums[u]});
}
}
}
}
return res;
}
};



